Capacitor and Coil

Electricity and Magnetism Level 2

[A] is a circuit connected in series with a capacitor, a light bulb and an AC power supply. [B] is a circuit connected in series with a coil, a light bulb and an AC power supply. The AC power supply and the light bulb are the same for both A and B . How will the brightness of the bulbs in A and B change, respectively, if we increase the frequency of the AC power supply?

The RMS electrical power value of the AC power supply is constant.

A will darken and B will brighten. A will brighten and B will darken. A and B will brighten. A will brighten and B will not change.

Lakshan Dumpa by Lakshan Dumpa , 24, India

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3 solutions

Arijit Banerjee
Mar 4, 2014

Capacitive reactance(Xc) is inversely proportional to frequency while Inductive reactance(XL) is directly proportional to frequency . Therefore on increasing frequency Xc decreases hence current increase and just the vice versa occurs in the other 1

2 Helpful 0 Interesting 0 Brilliant 1 Confused
Densen Puthussery
Feb 27, 2014

capacitor acts as short circuit for higher frequencies, while inductor offers more reactance when signal frequency is increased....

1 Helpful 0 Interesting 0 Brilliant 0 Confused

As indictive reactance of inductor is directly propotional to the frequency And capacitive reactance of capacitor is inversly proportional to the frequency So more the reactance less the brightness

Rishi Gupta - 7 years, 3 months ago
Zohurul Islam
Aug 25, 2014

With the increase in frequency, the capacitive reactance decreases whereas the inductive reactance increases. So, at higher frequency, more current will flow in circuit A than the current in circuit B. Thus, the bulb in circuit A will brighten but the bulb in circuit B will darken.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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