Capacitor collision

Two fixed very large conducting plates A A and B B of area S S carry charges Q -Q and q q respectively, where Q > q > 0 Q > q > 0 . A third identical plate C C carrying a charge Q Q is released at distance d d from B B . Third plate collides with B B . Assume collision is elastic and time of collision is sufficient to redistribute charge among B B and C C (neglect gravity):

A: Force acting on plate C C before collision is ( Q q ) Q 2 ϵ 0 S \dfrac {(Q-q)Q}{2\epsilon_0 S} .

B: Force acting on plate C C after collision is ( q / 2 ) 2 2 ϵ 0 S \dfrac {(q/2)^2}{2\epsilon_0 S} .

C: Subsequent to collision kinetic energy of plate C C increases.

D: Subsequent to collision electrostatic potential energy between the plates remains constant.

A, B A, B, C, D A, B, D B, C, D B, D None of the others

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1 solution

Avi Solanki
Jan 21, 2017

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