The above two diagrams show capacitors A and B, with their respective capacities
0
.
5
μ
F and
2
μ
F, connected to an electric circuit in two different ways. The one on the left is a series connection, while the one on the right is a parallel connection. What are the combined capacitance in the above left(
C
s
) and right(
C
p
) diagrams, respectively?
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THE SERIES
C t o t a l 1 = 0 . 5 1 + 2 1
C t o t a l 1 = 2 4 + 1
C t o t a l = 5 2
C t o t a l = 0 . 4
THE PARALLEL
C t o t a l = 2 + 0 . 5
C t o t a l = 2 . 5
when the capacitors are connected in series the equivalent capacitance id given by Ceq = C1 * C2 / (C1 + C2) when the capacitors are connected in parallel the equivalent capacitance is given by Ceq = C1 + C2
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When capacitors are in series 1/Ceq = (1/C1) + (1/C2) + (1/C3).............. where C1 , C2 , C3 ..... are capacitors in series and Ceq is equivalent capacior. For this case 1/Ceq = 1/0.5 + 1/2 => Ceq = 2*0.5/2.5 = 0.4 uF
When Capaciors are in parallel Ceq = C1 + C2 + C3 ......... C1, C2 , C3 .... are capacitors in parallel IN this case Ceq = 2 + 0.5 = 2.5 uF