Capacity of Capacitor

The above two diagrams show capacitors A and B, with their respective capacities 0.5 0.5 μ \mu F and 2 2 μ \mu F, connected to an electric circuit in two different ways. The one on the left is a series connection, while the one on the right is a parallel connection. What are the combined capacitance in the above left( C s C_s ) and right( C p C_p ) diagrams, respectively?

0.4 μ \mu F and 2.5 μ \mu F 1.5 μ \mu F and 2.5 μ \mu F 2.5 μ \mu F and 1.5 μ \mu F 0.4 μ \mu F and 1.5 μ \mu F

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4 solutions

Shubhendu Anupam
Feb 21, 2014

When capacitors are in series 1/Ceq = (1/C1) + (1/C2) + (1/C3).............. where C1 , C2 , C3 ..... are capacitors in series and Ceq is equivalent capacior. For this case 1/Ceq = 1/0.5 + 1/2 => Ceq = 2*0.5/2.5 = 0.4 uF

When Capaciors are in parallel Ceq = C1 + C2 + C3 ......... C1, C2 , C3 .... are capacitors in parallel IN this case Ceq = 2 + 0.5 = 2.5 uF

ok

Debi Das - 7 years, 3 months ago
Rahma Anggraeni
May 12, 2014

THE SERIES

1 C t o t a l = 1 0.5 + 1 2 \frac{1}{C_{total}}=\frac{1}{0.5}+\frac{1}{2}

1 C t o t a l = 4 + 1 2 \frac{1}{C_{total}}=\frac{4+1}{2}

C t o t a l = 2 5 C_{total}=\frac{2}{5}

C t o t a l = 0.4 C_{total}=\boxed{0.4}

THE PARALLEL

C t o t a l = 2 + 0.5 C_{total}=2+0.5

C t o t a l = 2.5 C_{total}=\boxed{2.5}

Tayyaba Siddiqua
Feb 22, 2014

That was easy! :)

when the capacitors are connected in series the equivalent capacitance id given by Ceq = C1 * C2 / (C1 + C2) when the capacitors are connected in parallel the equivalent capacitance is given by Ceq = C1 + C2

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