A car and a truck are moving side by side on a road with the same velocity. At one point, the drivers of the two vehicles apply the brakes at exactly the same time.
Which vehicle will travel a larger distance before coming to rest?
Assume that the two vehicles have the same braking force and also take mass of truck is more than that of car.
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If the truck and car are travelling on a smooth friction-less road , how do they even stop at all?
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If friction is present then will the result be same or not. I had that doubt and hence mentioned it as frictionless surface
But brakes do apply friction on the tire
I agree with Michael Mendrin: if there is no friction neither vehicle will be able to stop. Furthermore, I disagree with the assumption that the "two vehicles have the same braking force". That does not make sense since a truck has much larger and stronger brakes. In many practical situations the truck stops faster, because it employs pneumatic breaks.
Elementary calculation with a simple model for the friction would tell us that if the brakes are applied at full force and the wheels lock, the two vehicle will stop over the same distance.
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I should have assumed more than given about the same (or compensatory designed) tires(coefficient of friction) because tires behave differently on different suspension systems, non-skid technology or braking skill, aerodynamics, ....
@Laszlo Mihaly i agree with you.
F is the resultant force, m is the mass and a is the acceleration. Using Newton's Second Law, we have that F = m a . Since F c a r = F t r u c k , and m c a r < m t r u c k , we have that a c a r > a t r u c k . Therefore, the truck will travel for a larger distance.
The truck will travel a larger distance than the car because the truck is heavier.
*It has more momentum due to its larger mass
Yes heavy vehicle should apply brake much before stop.:)
HOW DO YOU KNOW THAT THE TRUCK IS HEAVIER
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it was not mentioned in the problem but it is just common sense to assume that the truck is heavier
As the truck has more mass than the car but the braking forces are identical. The braking force of the truck will have to take more time to stop it.
A heavier mass has more inertia so the truck will have a larger tendency to keep moving and hence will travel a larger distance than the car.
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Let the mass of the truck be M and mass of the car be m such that M > m . It is given that both the vehicles travel with same velocity, let us say v .
Momentum of the truck : P 1 = M × v = M v
Momentum of the car : P 1 = m × v = m v
Now, P 1 > P 1 since M v > m v . So the truck will have larger momentum than the car.
∴ The truck will travel for a longer distance before coming to rest.