Card Game "24"

Algebra Level 3

24 is a card game where users draw 4 cards at a time from a regular deck of cards.

The cards are their value. Here, Jacks = 11, Queens = 12, and Kings = 13, Ace = 1

The objective of the game is to use only Parenthesis, Addition, subtraction, multiplication and division on the 4 numbers to make 24. Each digit is its own separate number, and you cannot introduce zeros or decimal places. All 4 numbers must be used.

For example 1 , 3 , 4 , 6 1, 3, 4, 6 has a solution of 6 1 3 4 \frac{6}{1-\frac{3}{4}}

Consider the following set. Which two do not have a solution?

A) 3 , 3 , 8 , 8 3, 3, 8, 8

B) 2 , 3 , 5 , Q u e e n 2, 3, 5, Queen

C) 2 , 3 , 9 , J a c k 2, 3, 9, Jack

D) 5 , 5 , 5 , A c e 5, 5, 5, Ace

E) 3 , 3 , 7 , 10 3, 3, 7, 10

Submit the product of the two letters that have no solutions where A = 2 , B = 3 , C = 5 , D = 7 , E = 11. A = 2, B = 3, C = 5, D = 7, E = 11.


The answer is 55.

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1 solution

Timothy Cao
Apr 3, 2018

8/(3 - 8/3) = 24

12/(3 - 5/2) = 24

5 (5 - 1/5) = 24

By elimination, since there are only two left, C and E must be the ones without solutions as the question asks for two. C = 5 and E =11 and so the answer is 55

I think that this question should be number theory or logic rather than algebra

Adrian Ma - 1 year, 1 month ago

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