Carpenter

Algebra Level pending

Carpenter A and carpenter B completes a job if A works 2 days and B works 3 days, or if both works 2 2 5 \frac{2}{5} days. How long would it take each to do the job alone?

5 and 6 4 and 6 4 and 3 5 and 7

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1 solution

Zee Ell
Sep 16, 2016

Let a be the part (or percentage, in decimal form) of the job, what carpenter A can complete on his own in 1 day and b the part of the job what carpenter B can do in 1 day alone.

Then it is easy to see, that the number of days needed (to complete the job alone) for:

• Carpenter A is 1 a \text {• Carpenter A is } \frac {1}{a}

• Carpenter B is 1 b \text {• Carpenter B is } \frac {1}{b}

(E. g. if a = 0.1 (Carpenter A can do 10 % of the job in 1 day, working alone), then 1 a = 1 0.1 = 10 \frac {1}{a} = \frac {1}{0.1} = 10 days are needed for Carpenter A to complete the job alone.)

Now, we can set up the following equations:

2a + 3b = 1 .... (i)

2.4a + 2.4b = 1 .....(ii)

Solving the simultaneous equations:

6(i) - 5(ii):

6b = 1

b = 1 6 b = \frac {1}{6}

Substituting b back into (i):

2 a + 3 6 = 1 2a + \frac {3}{6} = 1

2 a = 1 2 2a = \frac {1}{2}

a = 1 4 a = \frac {1}{4}

By calculating the reciprocals of a and b, we get our answer:

4 and 6 \boxed { \text {4 and 6} }

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