Carpenter A and carpenter B completes a job if A works 2 days and B works 3 days, or if both works 2 days. How long would it take each to do the job alone?
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Let a be the part (or percentage, in decimal form) of the job, what carpenter A can complete on his own in 1 day and b the part of the job what carpenter B can do in 1 day alone.
Then it is easy to see, that the number of days needed (to complete the job alone) for:
• Carpenter A is a 1
• Carpenter B is b 1
(E. g. if a = 0.1 (Carpenter A can do 10 % of the job in 1 day, working alone), then a 1 = 0 . 1 1 = 1 0 days are needed for Carpenter A to complete the job alone.)
Now, we can set up the following equations:
2a + 3b = 1 .... (i)
2.4a + 2.4b = 1 .....(ii)
Solving the simultaneous equations:
6(i) - 5(ii):
6b = 1
b = 6 1
Substituting b back into (i):
2 a + 6 3 = 1
2 a = 2 1
a = 4 1
By calculating the reciprocals of a and b, we get our answer:
4 and 6