catching a bus...
Classical Mechanics
Level
2
A man is standing at point P , he sees a bus leaving a halt a few meters away from him at a constant accelaration so the man runs after the bus at a velocity of u . He finaly boards the bus at time T , what is the accelaration of the bus ?
can only be UT
can only be u/T
can't tell due to lack of information
can only be 2U/T
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1 solution
suppose the distance between the man and the bus was x. Now the distance travelled by the bus(s) in time T (from second equation of motion) would be. s=(aT^2)/2
now the man has to travelled x+s distance in time T with velocity U so the relation is U= (x+s)/T UT=x+s UT-x=s substituiting the value of s from above
(aT^2)/2 = UT-x aT^2 = 2(UT-x) a = 2(UT-x)/T^2 now since x is not given and none of the answer matches there fore the only option we have is can't tell due to lack of information .