catching can

Classical Mechanics Level 4

A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch of road. A boy riding on the back of the truck throws a can of soda upward and catches the projectile at the same location on the truck bed, but 16.0 m farther down the road. determine the initial velocity of the can (in m/s)


The answer is 12.6.

Arpit Dhimanj by Arpit Dhimanj , 23, India

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2 solutions

Chew-Seong Cheong
Jul 30, 2014

The time of flight of the can is t = 16 9.50 = 1.684 t = \frac{16}{9.50}=1.684 s. The time for the can to reach the apex is t 2 \frac{t}{2} s. And the initial upward velocity of the can u = g × t 2 = 9.8 × 0.842 u=g\times \frac{t}{2}=9.8\times 0.842 = 8.253 = 8.253 m/s. Therefore, the initial velocity of the can v = 8.25 3 2 + 1 6 2 ≈ 12.6 v=\sqrt{8.253^2+16^2}\approx \boxed {12.6} m/s.

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Charlz Charlizard
Jun 14, 2014

as the truck is moving with constant velocity V , time of flight of ball is t=16/9.5 .so time for reachin max. height will be =8/9.5 .so Vsin€=10*(8/9.5) and we have Vcos€=9.5 .now solve the equation for V, and approx the ans.

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