A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch of road. A boy riding on the back of the truck throws a can of soda upward and catches the projectile at the same location on the truck bed, but 16.0 m farther down the road.
determine the initial velocity of the can (in m/s)
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The time of flight of the can is t = 9 . 5 0 1 6 = 1 . 6 8 4 s. The time for the can to reach the apex is 2 t s. And the initial upward velocity of the can u = g × 2 t = 9 . 8 × 0 . 8 4 2 = 8 . 2 5 3 m/s. Therefore, the initial velocity of the can v = 8 . 2 5 3 2 + 1 6 2 ≈ 1 2 . 6 m/s.