Cauchy's Conundrums

Calculus Level 4

Let C C be a contour defined by the function γ : [ 0 , 1 ] C , γ ( t ) = e 4 π i t + e 8 π i t \gamma : \left [ 0, 1 \right ] \rightarrow \mathbb{C}, \gamma(t) = e^{4\pi i t} + e^{8\pi i t}

Then evaluate γ z 3 d z \LARGE{\oint_\gamma z^{3}} \, dz .


The answer is 0.

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2 solutions

James Yang
Nov 7, 2016

Any analytic function integrated on any closed contour with no singularities has integral value of 0 (Cauchy Integral Theorem).

An open set Ω C \Omega \subset \mathbb{C} is said to be holomorphically conected if it is a conected open set and f H ( Ω ) , F H ( Ω ) / F ( z ) = f ( z ) z Ω \forall f \in \mathcal{H} (\Omega), \space \exists F \in \mathcal{H} (\Omega) \space / \space F '(z) = f(z) \space \forall z \in \Omega .

In this case, C \mathbb{C} is a holomorphically conected set and in these sets is fullfiled γ f ( z ) d z = 0 , f H ( C ) \oint \gamma f(z) dz = 0, \space \forall f \in \mathcal{H} (\mathbb{C}) being γ \gamma a regular closed path.

Of course, in this case the function f ( z ) = z 3 f(z) = z^3 is a holomorphic function in C \mathbb{C} and γ \gamma is a regular closed path...

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