Let C be a contour defined by the function γ : [ 0 , 1 ] → C , γ ( t ) = e 4 π i t + e 8 π i t
Then evaluate ∮ γ z 3 d z .
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An open set Ω ⊂ C is said to be holomorphically conected if it is a conected open set and ∀ f ∈ H ( Ω ) , ∃ F ∈ H ( Ω ) / F ′ ( z ) = f ( z ) ∀ z ∈ Ω .
In this case, C is a holomorphically conected set and in these sets is fullfiled ∮ γ f ( z ) d z = 0 , ∀ f ∈ H ( C ) being γ a regular closed path.
Of course, in this case the function f ( z ) = z 3 is a holomorphic function in C and γ is a regular closed path...
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Any analytic function integrated on any closed contour with no singularities has integral value of 0 (Cauchy Integral Theorem).