Center of mass of car

Classical Mechanics Level 2

Suppose that the center of mass of an empty $1450$ kg car is $2.20 \text{ m}$ from the front of the car. Now, two people sit in the front seat and three people sit in the back seat, $2.80 \text{ m}$ and $3.90 \text{ m}$ from the front of the car, respectively. How far is the new center of mass of the car from the front of the car?

Assume that each person has a mass of $70 \text{ kg.}$

2.45 m 3.90 m 2.80 m 1.50 m

1 solution

Tasnia Nowrin
Aug 9, 2014

center of mass x = $\frac{m1*x1+ m2 * x2+m3 *x3}{m1+m2+m3}$

m1=1450, x1=2.20

m2=140 (2 people in the front so m2=2*70), x2=2.80

m3= 210 (3 people in the back) , x3 = 3.90

x = $\boxed{2.45}$

Center of mass of car

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