Chain! Not again!
A chain of mass per unit length ¥ and length 1.5m rests on a fixed smooth sphere off radius R=2/π metre such that“A” end of a chain is at top of the sphere while the other end is hanging freely . Chain is held stationary by a horizontal thread PA. The tension in the thread is:
Fig:
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1 solution
The portion in contact with the sphere is 2 ∗ π ∗ R ∗ 4 1 = 2 ∗ π ∗ π 2 ∗ 4 1 = 1 m . During this, the chain losses a hight of R m = π 2 m ∴ h a n g i n g p o r t i o n = 1 . 5 − 1 = 2 1 . So the total tension is Y ( π 2 + 2 1 . )