Challenging equation that have exponential variable

Algebra Level 1

Solve for x x : 3 x + 3 x + 2 3 = 267 3^{x} + 3^{x + 2} - 3= 267


The answer is 3.

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3 solutions

To find x .
In the eqution,
3 x 3^{x} + 3 x + 2 3^{x+2} -3=267
3 x 3^{x} + 3 x + 2 3^{x+2} =270
3 x 3^{x} + 3 x + 2 3^{x+2} = 3 3 3^{3} ×10
Now on comparing ,
3 x 3^{x} = 3 3 3^{3}
x x = 3 3


Same solution here, thanks for posting it :)

Don Ramon De Jesus - 5 years, 8 months ago

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Thanks! :)

A Former Brilliant Member - 5 years, 8 months ago

Instead of comparing we can just do this instead, 3 x ( 1 + 3 2 ) = 270 3 x × 10 = 270 3 x = 27 3^{x}(1+3^2) = 270 \Rightarrow 3^{x} \times 10 =270 \Rightarrow 3^x =27 Now its quite obvious that x = 3 x=\boxed{3}

Athiyaman Nallathambi - 5 years, 8 months ago
Mohit Gupta
Oct 3, 2015

Well sorry to say that but in what terms is this eqn. challenging??????????

Mohammad Khaza
Jul 7, 2017

3^x + 3^(x+2) - 3=267

or, 3^x(1 + 3^2) =270

or,3^x . 10 =270

or, 3^x = 27

or, 3^x = 3^3

or, x=3

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