When ships come in to dock where the berths are extremely narrow, the ships need to be towed in to prevent damage to both the dock and the ship. A metal cable is attached to the front of the ship, looped through a pulley that is hinged at the edge of the dock, and attached to an automated winch.
If the automated winch winds the cable at a constant rate, which of the following describes the speed at which the boat will be pulled in (prior to reaching the dock)?
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Most people think that the boat can only move less than the change in the distance moved by the rope. However, this is not true, and we can demonstrate it as such:
Let D be the point on the dock. Let X 1 be the initial point on the boat, let X 2 be the final point on the boat after it moved for 1 second. The problem tells us that D X 1 − D X 2 is the contraction of the length of the rope.
Hence, by the triangle inequality, we get that X 1 X 2 + D X 2 > D X 1 or that X 1 X 2 > D X 1 − D X 2 = 1 0 . Hence, the boat moves more the contraction of the length of the rope.
How do you know D X 1 − D X 2 = 1 0 ?
Sorry, I used that value in the other question. What I should have said was X 1 X 2 is the distance that the boat moved, which is greater than the speed at which the cable is pulled in. Edited my previous comment.
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Let speed of pulling the cable be v .
y 2 = x 2 + c 2 ⟹ 2 y d t d y = 2 x d t d x ⟹ x y v = d t d x ⟹ s i n θ v = d t d x
As θ decreases, s i n θ decreases and as a result s i n θ v increases. Thus, speed of boat, i.e., d t d x increases over time.