Charged pendulum

Let the period of an uncharged pendulum be t t . This pendulum is now charged with a charge of + q +q and placed in a uniform electric field pointing vertically upward. If the new period of the pendulum is denoted by T , T, which of the following is correct?

t t is equal to T T t t is less than T T t t is greater than T T Nothing can be said about T T

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1 solution

Arghyanil Dey
Apr 16, 2014

Period of pendulum = 2 π l g \text{Period of pendulum} = 2\pi\sqrt{\dfrac{l}{g}}

Once the electric field is turned on, the effective value of g g is reduced. Therefore, t t is less than T T .

You cant say that, as it's not given whether L is >1 or <1 !!

Utkarsh Bhardwaj - 5 years, 7 months ago

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t/T is independent of l, if l is fixed

Nimish Dwarakanath - 5 years, 1 month ago

Time period has inverse relation with g.. That means if g decreases then time period should increase

Faizan Shabir - 5 years, 4 months ago

And what if E is greater than 2mg in magnitude?

Jake Ok - 5 years ago

Obviously if E

Jake Ok - 4 years, 7 months ago

I was thinking the same as what @Jake Ok said. The question should be made clearer.

Vibhav Aggarwal - 3 years, 2 months ago

I agree with Vibhav. This is poorly phrased.

Don Weingarten - 2 years, 4 months ago

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