A non-conducting ring of mass and radius , the charge per unit length is shown in figure. It is then placed on a rough non-conducting horizontal plane. At time , a uniform electric field is switched on and the ring starts rolling without sliding. Find the frictional force acting on the ring.
Given -
Find the value of .
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Net electric force is zero, so the linear acceleration is the force of friction divided by the mass. Since it rolls without slipping, the angular acceleration is the linear acceleration divided by the radius. Therefore we have:
α = m R f
The differential charge is λ R d θ and so if θ is measured with respect to the horizontal, then the torque from the electric force will be 2 λ E 0 R 2 0 ∫ π / 2 s i n θ d θ = 2 λ E 0 R 2
(The factor of 2 comes from symmetry: the torque from the negative charge is the same as the torque from the positive charge.)
Friction will oppose the rotation caused by the electric force, so it will supply an opposite torque, therefore we have:
τ = 2 λ E 0 R 2 − f R = I α = m R 2 α = f R
Solving yields f = λ E 0 R