Charges And Conducting Sheet

Two charges are placed above an infinite conducting sheet as shown. The first has charge 6 q -6q and is placed a distance d d above the sheet, whereas the second has charge 6 q 6q and is placed a distance d d directly above the first (so that it is a total distance 2 d 2d away from the sheet).

Where k = 1 / ( 4 π ϵ 0 ) k = 1/(4\pi\epsilon_0) , suppose F = C k q 2 / d 2 F = C \cdot kq^2/d^2 represents the magnitude of the force on the first charge (of charge 6 q -6q ). What is C C ?


The answer is 31.

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1 solution

Lawrence Chiou
Mar 16, 2016

By the method of image charges, Laplace's equation is satisfied for the configuration if image charges of charge 6 q 6q and 6 q -6q are placed, respectively, a distance d d and 2 d 2d below the sheet, collinear with the two charges above the sheet.

Such a configuration leads to a net force on the charge of 6 q -6q of

F = k 36 q 2 d 2 k 36 q 2 4 d 2 + k 36 q 2 9 d 2 = 31 k q 2 d 2 . F = k\frac{36q^2}{d^2} - k\frac{36q^2}{4d^2} + k\frac{36q^2}{9d^2} = 31k\frac{q^2}{d^2}.

Therefore, C = 31 C = 31 .

I think answer should be 41 as you have mistaken in sign and direction. Please check it.

Navneet Prabhat - 4 years, 7 months ago

I think this method is valid only when the infinite sheet is grounded.

Am i right or there's something more to it?

neelesh vij - 5 years, 1 month ago

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In this case, the result is the same regardless of whether the sheet is grounded. See, for instance, https://www.physicsforums.com/threads/point-charge-above-infinite-conducting-plane.775088/

Lawrence Chiou - 5 years, 1 month ago

Do and is correct

Satyam Tripathi - 4 years, 6 months ago

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