Chase the angle if you can

Geometry Level 1

Triangle D E C DEC is inscribed in a circle with center at O O . Line A B AB is a tangent to the circle at C C . E D C = 4 5 \angle EDC=45^\circ and D C A = 5 0 \angle DCA=50^\circ . Find D O E \angle DOE .

17 5 175^\circ 16 0 160^\circ 14 5 145^\circ 17 0 170^\circ

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Christian Daang
Oct 19, 2017

Note that arc( D C = 2 5 0 = 10 0 DC = 2*50^{\circ} = 100^{\circ} ) and arc( C E = 2 4 5 = 9 0 CE = 2*45^{\circ} = 90^{\circ} )

Hence, D O E = arc E D = 36 0 ( 10 0 + 9 0 ) = 17 0 \angle DOE = \text{arc} \ ED = 360^{\circ} - (100^{\circ} + 90^{\circ}) = \boxed{170^{\circ}} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...