Chasing the angle is not work anymore

Geometry Level pending

A B C \triangle ABC is a isosceles triangle which B C = C A BC=CA and B C A = 20 ° \angle BCA=20°\quad
Given D C = A B DC=AB . What is the angle of C B D \angle CBD in degree.


The answer is 10.

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1 solution

Ratul Pan
Oct 28, 2015

Let C B D \angle CBD = x, D B A \angle DBA = y and C D B \angle CDB =z
x+y=80 (isosceles triangle)
x+z=160(angle sum theory)
y+z=100(angle sum theory)
solving x.y.z we find
x=10= C B D \angle CBD


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