A milkman cheats his customers by adding water to the milk he sells. He starts the day with 1000 litres of milk.However, after selling every 500 litres of milk, he adds an equal quantity of water to what he already has. The milkman can get away by cheating as long as the milk to water ratio does not fall below 1 : 7. Each customer buys exactly 2 litres of milk a day (except for the first 100 who buy 5 litres each). The total number of customers the milkman has cheated if he ends up selling all the milk is :
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
initially milk man has 1000 litres pure milk of which pure 500 litres are given to those 100 who are buying 5 litres
now cheating starts....500L milk +500L water ----milk:water ----1:1
after selling the 500L milk from the above mixture he has cheated 250 poeple.
cheating time 500L(1:1) mixture + 500L water -----milk:water now becomes ---1:3
again after selling the 500L milk from the above mixture he has cheated another 250 people.
cheating time 500L(1:3) mixture +500L water-------milk:water now becomes ----1:5
again after selling the 500L milk from the above mixture he has cheated another 250 people.
chetaing time 500L(1:5) mixture +500 L water ---------milk:water now becomes-----1:7
again after selling the 500L milk from the above mixture he has cheated another 250 people.
now ,he can't add further water ,otherwise milk water ratio exceeds 1:7 .so still now he cheated 4X250=1000.
he cheated 1000 people.