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find the remainder when 3 6 36 36 36^{{36}^{36} } is divided by 37.

2 36 7 1 5 35

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1 solution

Maggie Miller
Jul 30, 2015

Note 3 6 36 36^{36} is even and 36 1 ( m o d 37 ) 36\equiv -1\pmod{37} . Then 3 6 3 6 36 ( 1 ) 3 6 36 ( m o d 37 ) 1 ( m o d 37 ) 36^{36^{36}}\equiv (-1)^{36^{36}}\pmod{37}\equiv\boxed{1}\pmod{37} .

Very nice and clear solution.the same as of mine.upvoted

abhigyan adarsh - 5 years, 10 months ago

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