In a beaker conatining gm of pure chalk, gm of sodium and gm of pure hydrochloric acid are added. Then gm of pure water, gm of chlorine molecule and gm of carbon atoms are removed from the beaker. If all these reactants react to form a chemical compund without any wastage of any reactant, then what is the maximum number of moles that can be present in the reacting compound?
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Gram molecular mass of C a C O 3 is 4 0 + 1 2 + 3 ( 1 6 ) = 1 0 0 gm
So, number of moles of C a C O 3 is 1 0 0 5 0 = 2 1
Gram atomic mass of N a is 2 3 gm
So, number of moles of N a is 2 3 4 6 = 2
Gram molecular mass of H C l is 1 + 3 5 . 5 = 3 6 . 5 gm
So, number of moles of H C l is 3 6 . 5 7 3 = 2
Gram atomic mass of C is 1 2 gm
So, number of moles of C is 1 2 4 = 3 1
Gram molecular mass of C l 2 is 2 × 3 5 . 5 = 7 1 gm
So, number of moles of C a C O 3 is 7 1 3 5 . 5 = 2 1
Gram molecular mass of H 2 O is 2 ( 1 ) + 1 6 = 1 8 gm
So, number of moles of H 2 O is 1 8 9 = 2 1
So, the maximum number of moles of the resulting element is ( 2 1 + 2 + 2 ) − ( 3 1 + 2 1 + 2 1 )
= 2 2 1 − 1 3 1
= 6 7
= 1 . 1 6 7 moles.