Chemistry 10

Chemistry Level 2

A positron is emitted from 11 23 N a _{11}^{23}Na . The ratio of the atomic mass and atomic number of the resulting nuclide is


Try more chemistry problems here
23 10 \dfrac{23}{10} 23 12 \dfrac{23}{12} 22 11 \dfrac{22}{11} 22 10 \dfrac{22}{10}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Chew-Seong Cheong
Sep 22, 2015

The emission of a positron with negligible mass only reduces the atomic number by 1 1 . Therefore, the ratio of atomic mass and atomic number of the resulting nuclide is 23 11 1 = 23 10 \dfrac{23}{11-1} = \dfrac{23}{10} .

Did in the same way.

Sai Ram - 5 years, 8 months ago

Is there a wiki for that?

Mr Yovan - 4 years, 10 months ago

Log in to reply

I don't think so.

Chew-Seong Cheong - 4 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...