Chemistry Daily Challenge 18-July-2015

The EMF of a cell corresponding to the reaction

$\text{Zn}(s)+2\text{H}^+(aq) \to \text{Zn}^{+2}(0.1\text{ M})+\text{H}_2(g,1 \space \text{atm})$

is 0.28 volts at 298 K.

$\color{#3D99F6}{\text{Calculate the pH of the solution at the hydrogen electrode.}}$

$\begin{aligned} E_{\text{Zn}^{2+}|\text{Zn}}&=-0.76\text{ V}\\ E_{\text{H}^{+}|\text{H}_2}&=0\text{ V} \end{aligned}$