Chemistry Daily Challenge 27-July-2015

Chemistry Level 2

What are the respective numbers of α \alpha and β \beta particles emitted during the transformation of 90 Th 232 _{90}\text{Th}^{232} to 82 Pb 208 ? _{82}\text{Pb}^{208}?

2, 2 4, 2 6, 4 8, 6

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Aamir Faisal Ansari by Aamir Faisal Ansari , 24, India

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1 solution

90 T h 232 → 82 P b 208 + x ( 2 H e 4 ) + y ( − 1 e 0 ) \large \color{#3D99F6}{_{90}Th^{232}}\to \color{#3D99F6}{_{82}Pb^{208}}+\color{#D61F06}{x}\space \color{#3D99F6}{(_2He^4)}+\color{#D61F06}{y}\space \color{#3D99F6}{(_{-1}e^0})

232 = 208 + 4 x + 0 y a n d 90 = 82 + 2 x − y \large 232=208+4x+0y \quad and \quad 90=82+2x-y

Solving above equation gives x = 6 a n d y = 4 \large x=6\quad and \quad y=4

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