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Chemistry Level 3

The total number of p π − d π p \pi - d \pi bonds in the following compounds is S.

Input S+1.


The answer is 6.

Md Zuhair by Md Zuhair , 20, India

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1 solution

Parth Sankhe
Dec 10, 2018

The only p π pπ type atom in the question is O O (all others are d π dπ ), and in all cases it is doubly bonded with other atoms. Thus, we only have to find the total number of bonds consisting O O , which is 6.

1 Helpful 1 Interesting 0 Brilliant 2 Confused

Hmmm... Nicely done :)

Md Zuhair - 2 years, 6 months ago

How? I don't feel this logic is correct, in every atom whose O is a part, has sp3 hybridization, however it is not so in So2 which has 2 O atoms (sp2) hence pi bond first forms by the p orbital, hence only one of those 2 O atoms will make a p pi-d pi bond.

Shreyansh Mukhopadhyay - 1 year, 11 months ago

This is horribly wrong. First of all, S=5. There are only 5 pπ-dπ bonds overall. AND we had to answer S+1, which means 6. All the S=O \text{S=O} bonds are not p π − d π p \pi - d \pi , eg in SO 2 ( O=S=O ) \text{SO}_2 \text{ ( O=S=O ) } there is only one p π − d π p \pi - d \pi bond, the other being 3 p π − 2 p π 3p \pi - 2p \pi .

Harsh Poonia - 1 year, 9 months ago

1 pending report

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