Chemistry - Part 1

Chemistry Level 2

The most perilous incident, the World War IV has just been fought between the Angels and Demons. The Demons, tried their best to annihilate the Angels by firing a deadly poisonous gas on them.

The Angels, too, wanted to stop the catastrophe. Thus they started finding more about the gas. On their chary scrutiny, the gas was found to be $1.1\times10^{8}\text{ kg}$ of phosgene .

They created a counter-gas, each molecule of which could stop the effect of each molecule of phosgene.

How many molecules of the counter-gas do the Angels need to prevent the demise of their fellow mates?

1.9\times10^{-15}

6.7\times10^{29}

6.7\times10^{32}

2.9\times10^{-15}

4 solutions

Agnishom Chattopadhyay
May 15, 2014

Phosgene is $COCl_2$

Its molecular weight = 98.92 g mol^(−1)

Mathematica Code:

(1.1 10^8 kg)/((0.09892 kg)/mol) /. mol -> 6.023 10^23

Returns: 6.69763*10^32

phosgene was used already in ww1

Radha Krishnan B - 7 years ago

Come on! D'you want me to use bones and sticks instead!!!

Satvik Golechha - 7 years ago

NICE QUESTION

Ronnel Einstein - 7 years ago

Thanks. ;D I dunno why I can't simply reply "thanks" when it is sufficient to do so.

Satvik Golechha - 7 years ago

Kenny Lau
Jul 9, 2014

The formula of phosgene is $COCl_2$ .

Therefore, its molar mass = $12.01+16.00+35.45\times2=98.9 \mbox{g}\cdot\mbox{mol}^{-1}$

$1.1\times10^8\mbox{kg}$ of phosgene contains $1.1\times10^8\mbox{kg}\times\frac{1000\mbox{g}}{1\mbox{kg}}\times\frac{1\mbox{mol}}{98.9\mbox{g}}\times\frac{6\times10^{23}\mbox{molecules}}{1\mbox{mol}}=6.7\times10^{32}$ molecules.

did the same thing

Mardokay Mosazghi - 6 years, 6 months ago

Deeksha Das
Jul 5, 2014

Given mass = 1.1 x 10^8 kg = 1.1 x 10^11 g Molecular mass of COCl2 = 99 u 99 g of COCl2 = 1 mole 1.1 x 10^11 g of COCl2 = 1.1 x 10^11 x 1/99 moles 1 mole has 6.023 x 10^23 molecules 1.1 x 10^11 x 1/99 x 6.023 x 10^23 molecules = 6.7 x 10^32 molecules For each molecule of COCl2, one molecule of the counter gas is required. So, for 6.7 x 10^32 molecules of COCl2, 6.7 x 10^32 molecules of the counter gas will be required.

Jeffrey J Robin
Jun 3, 2014

The Toxic or Poisonous gas Phosgene Has a chemical formula of COCL2 which has a Mr of 99g so 1.1x10^8 Kg should be converted to grams as to find the number of moles of Phosgene.. In grams 1.1x10^11 Phosgene No. Of Moles = 1.1x10^11/99 = 1111111111 moles So number of molecules = 1111111111x Avogadro number of particles = 1111111111x6.02x10^23 = 6.7x10^32 molecules

Chemistry - Part 1

4 solutions

0 pending reports