Chemistry (pH and pOH) #1

$pH = -log[H^{+}]$

$pH = -log 8 . 10^{-5}$

$pH = - (log 8 + log 10^{-5})$

$pH = - (log 2^{3} + log 10^{-5})$

$pH = - (3 log 2 - 5 log 10)$

$pH = - (3 . 0,3 - 5 . (log 2 + log 5))$

$pH = - (0,9 - 5 . (0,3 + 0,7))$

$pH = - (0,9 - 5 . 1)$

$pH = - (0,9 - 5)$

$pH = - (-4,1)$

$pH = + 4,1$

$pH = -log[H^{+}]$ $pH = -log 8 . 10^{-5}$ $pH = 5 - log 8$ $pH = 5 - 3 log 2$ $pH = 5 - 3*0.3$ $pH = 5 - 0.9$ $pH = 4.1$