Chemistry (pH and pOH) #2

Chemistry Level pending

If ( p O H = − l o g [ O H − ] ) (pOH = - log [OH^{-}]) , ( p H + p O H = 14 ) (pH + pOH = 14) ,

( l o g 2 = 0 , 3 ) (log 2 = 0,3) , ( l o g 10 = 1 ) (log 10 = 1) and ( l o g 3 = 0 , 45 ) (log 3 = 0,45) ,

find the pH when ( [ O H − ] ([OH^{-}] = 6.1 0 − 4 ) 6 . 10^{-4}) .

-10,75 -3,25 3,25 10,75

Victor Porto by Victor Porto , 22, Brazil

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2 solutions

Victor Porto
Sep 17, 2014

p O H = − l o g [ O H − ] pOH = -log[OH^{-}]

p O H = − l o g 6.1 0 − 4 pOH = -log 6. 10^{-4}

p O H = − ( l o g 6 + l o g 1 0 − 4 ) pOH = - (log 6 + log 10^{-4})

p O H = − ( l o g 2 + l o g 3 + l o g 1 0 − 4 ) pOH = - (log 2 + log 3 + log 10^{-4})

p O H = − ( l o g 2 + l o g 3 − 4. l o g 10 ) pOH = - (log 2 + log 3 - 4 . log 10)

p O H = − ( 0 , 3 + 0 , 45 − 4 ) pOH = - (0,3 + 0,45 - 4)

p O H = − ( 0 , 75 − 4 ) pOH = - (0,75 - 4)

p O H = − ( − 3 , 25 ) pOH = - (-3,25)

p O H = + 3 , 25 pOH = +3,25

p H + p O H = 14 pH + pOH = 14

p H = 14 − p O H pH = 14 - pOH

p H = 14 − ( 3 , 25 ) pH = 14 - (3,25)

p H = 10 , 75 pH = 10,75

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Abyoso Hapsoro
May 5, 2015

p O H = − l o g [ O H − ] pOH = -log[OH^{-}] p O H = − l o g 6.1 0 − 4 pOH = -log 6. 10^{-4} p O H = 4 − l o g 6 pOH = 4 - log 6 p O H = 4 − l o g 2 − l o g 3 pOH = 4 - log 2 - log 3 p O H = 4 − 0.3 − 0.45 pOH = 4 - 0.3 - 0.45 p O H = 3.25 pOH = 3.25 p H = p K w − p O H pH = pKw - pOH p H = 14 − 3.25 pH = 14 - 3.25 p H = 10.75 pH = 10.75

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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