Cheryl's Age

Logic Level 2

Albert and Bernard now want to know how old Cheryl is.

Cheryl: I have two younger brothers. The product of all our ages (that is my age and the ages of my two brothers) is 144, assuming that we use whole numbers for our ages.

Albert: We still don't know your age. What other hints can you give us?

Cheryl: The sum of all our ages is the bus number of this bus that we are on.

Bernard: Of course we know the bus number, but we still don't know your age.

Cheryl: Oh, I forgot to tell you that my brothers have the same age.

Albert and Bernard: Oh, now we know your age.

So what is Cheryl's age?


This problem is the sequel of Cheryl's Birthday .


The answer is 9.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jordan Cahn
Dec 12, 2018

There are 18 unique was for three numbers to multiply to 144 144 : Sum 1 1 144 146 1 2 72 75 1 3 48 52 1 4 36 41 1 6 24 31 1 8 18 27 1 9 16 26 1 12 12 25 2 2 36 40 2 3 24 29 2 4 18 24 2 6 12 20 2 8 9 19 3 3 16 22 3 4 12 19 3 6 8 17 4 4 9 17 4 6 6 16 \begin{array}{ccc|c} & & & \text{Sum} \\ \hline 1 & 1 & 144 & 146 \\ 1 & 2 & 72 & 75 \\ 1 & 3 & 48 & 52 \\ 1 & 4 & 36 & 41 \\ 1 & 6 & 24 & 31 \\ 1 & 8 & 18 & 27 \\ 1 & 9 & 16 & 26 \\ 1 & 12 & 12 & 25 \\ 2 & 2 & 36 & 40 \\ 2 & 3 & 24 & 29 \\ 2 & 4 & 18 & 24 \\ 2 & 6 & 12 & 20 \\ \color{#D61F06} 2 & \color{#D61F06} 8 & \color{#D61F06} 9 & \color{#D61F06} 19 \\ 3 & 3 & 16 & 22 \\ \color{#D61F06} 3 & \color{#D61F06} 4 & \color{#D61F06} 12 & \color{#D61F06} 19 \\ \color{#D61F06} 3 & \color{#D61F06} 6 & \color{#D61F06} 8 & \color{#D61F06} 17 \\ \color{#D61F06} 4 & \color{#D61F06} 4 & \color{#D61F06} 9 & \color{#D61F06} 17 \\ 4 & 6 & 6 & 16 \end{array} There are two sums -- 17 17 and 19 19 -- for which knowing the sum doesn't uniquely determine the ages. Of these, only one -- ( 4 , 4 , 9 ) (4,4,9) -- has two of the ages the same. Thus Cheryl, the oldest sibling, is 9 \boxed{9} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...