A 2-digit number's ten's place is twice its unit digit. It must be divisible by:
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Let the units digit be A so the tens digit is 2 A . That means that the number can be expressed as 1 0 × ( 2 A ) + 1 × ( A ) = 2 0 × A + A = 2 1 × A .
Since 2 1 = 3 × 7 , 2 1 × A must be divisible by both 3 and 7.