Child Labor #7

Algebra Level 4

{ a 2 + a b + b 2 = 2 b 2 + b c + c 2 = 1 c 2 + c a + a 2 = 3 \large{\begin{cases} a^2 + ab + b^2 &= 2 \\ b^2 + bc + c^2 &= 1 \\ c^2 + ca + a^2 &= 3 \end{cases}}

Choose the correct option satisfying the above system of equations.

a, b, c are in A.P. a, c, b are in A.P. b, a , c are in A.P. None of the other choices.

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1 solution

Rajen Kapur
Sep 26, 2015

Three cyclic equations with unequal values show that a, b, and c are mutually unequal. Multiplying first equation by (a - b) gives a 3 b 3 = 2 ( a b ) a^3 - b^3 = 2(a - b) . Likewise b 3 c 3 = b c ; b^3 - c^3 = b - c; and c 3 a 3 = 3 ( c a ) c^3 - a^3 = 3(c - a) . Adding all the three, 0 = 2 a 2 b + b c + 3 c 3 a 0 = 2a - 2b + b - c +3c - 3a 2 c a b = 0 , 2 c = a + b . \rightarrow2c - a - b = 0,\rightarrow 2c = a+ b. Hence a, c, b are in A.P.

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