Children's Probabilities Challenge

A couple has two kids. One is a girl who was born on a Tuesday . What is the probability of the other one be a boy? (Assume that for any given pregnancy the respective probabilities that a male or female are conceived are the same. Assume that there is equally likehood to born in any day of the week)

14/27 2/3 1/3 1/2

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1 solution

Pop Wong
Aug 17, 2020

Without the birthday information, the possible sample space will { ( G , G ) , ( G , B ) , ( B , G ) } \{ (G,G), (G,B), (B,G) \} and hence Pr(the other is a boy) = 2 3 =\cfrac{2}{3}

Take into account the birthday information,

( G , G ) ( G i , G j ) (G, G) \Rightarrow (G_i, G_j) where i , j { M o n , T u e , . . . , S u n } i, j \in \{Mon, Tue, ..., Sun\}

  • possible sample space G G = { ( G T u e , G j ) , ( G i , G T u e ) } G G = ( G T u e , G j ) + ( G i , G T u e ) ( G T u e , G T u e ) = 7 + 7 1 = 13 GG= \{ (G_{Tue}, G_j) , (G_i , G_{Tue}) \} |GG| = |(G_{Tue}, G_j)| + (G_i , G_{Tue}) - |(G_{Tue}, G_{Tue})| = 7+7-1=13

( B , G ) ( B i , G T u e ) (B, G) \Rightarrow (B_i, G_{Tue}) where i { M o n , T u e , . . . , S u n } i \in \{Mon, Tue, ..., Sun\}

  • possible sample space B G = { ( B i , G T u e ) } , B G = 7 BG = \{ (B_i, G_{Tue}) \}, |BG| = 7

( G , B ) ( G T u e , B j ) (G, B) \Rightarrow (G_{Tue}, B_j) where j { M o n , T u e , . . . , S u n } j \in \{Mon, Tue, ..., Sun\}

  • possible sample space G B = { ( G T u e , B j ) } , G B = 7 GB = \{ (G_{Tue}, B_j) \}, |GB| = 7

Probability = favorable outcome possible outcome = 7 + 7 7 + 7 + 13 = 14 27 =\cfrac{\text{favorable outcome}}{\text{possible outcome}} = \cfrac{7+7}{7+7+13} = \cfrac{14}{27}

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