A teacher has 45 chocolates. After giving two chocolates to each student, she is left with 7 chocolates. Find the number of students in the class.
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total distributed=45-7=38 chocolates.
students=38/2=19.
Let number of students be
x
.
4
5
=
2
x
+
7
2
x
=
3
8
x
=
1
9
Easy just 45minus 7 equal to 38 As the say each student get 2 So you just have to divide 38/2 Answer is 19
Let x be the number of students. Then 2x+7=45 2x=45-7=38 x=19
Thats the perfect algebraic way to solve such problems. (y)
(45 - 7) /2 = 38/2 = 19
45-2x=7 (start with 45 subtract the binomial for each student getting 2 "as 2X" to equal 7 left over)
Then subtract 45 from each side 2X=7-45 Then -2X=-38
Then divide by negative 2, and X=19
Why is this wrong? Let N be the number of students. Twice their number subtracted from the total number of chocolates equals 7. In algebra: 45 - 2N = 7. 2N = 7 - 45. So... N = -19??
45-2n=7 -2n=7-45 2n=45-7 2n=38 N=19
just think logically, there is no way that a number of students is minus! (=w=)b
I did it in this way (mostly all did) Total chocolates = 45 Left= 7 Distributed = 45-7=38 Each student gets 2 chocolates So,38/2=19..... So there are 19 students
Total chocolates=45
Chocolates left=7
so chocolates distributed=45-7=38
Each student gets=2 chocolates
so number of students=38÷2=19
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