Choose A Cricket Team For ACC...

from 10 batsmen number ways of choosing 7 batsmen is 10C7 then from 7 bowlers number of ways of choosing 6 bowlers is 7C6 and from 3 Wk no. of ways of choosing 2 is 3C2. hence the answer is (10C7) (7C6) (3C2)=2520

The Answer is C(10,7) x C(7,6) x C(3,2)

= 120 x 7 x 2

= 2520

From $10$ batsmen we have to chose $7$ which is $10C7$ . Similarly for bowler and wicket keeper we get $7C6$ and $3C2$ respectively. Hence,the answer is their product $10C7×7C6×3C2=120×7×3=2520$ .

10C7 7C6 3C2

Simple Combinatorics problem: 10C7 * 7C6 * 3C2 = 10C3 * 7C1 * 3C1 = (10 9 8)/(3*2) * 7 *3 = 2520

(10!÷3!÷7!)(7!÷6!)(3!÷2!) =2520 ans

10C7 X 7C6 X 3C2 = 2520

Selecting 7 batsman from 10 means 10C7, selecting 6 bowler from 7 means 7C6 and selecting 2 w. keepers from 3 means 3C2..... Now combining them i.e. (10C7)(7C6)(3C2)=2520

10C7 7C6 3C2

7 Batsmen can be chosen from 10 in 10C7 ways,6 bowlers can be chosen from 7 in 7C6 ways,similarly 2 wicket keepers can be chosen from 3 in 3C2 ways , Since all of them are required to form a team the no. of ways is given by 10C7 * 7C6 * 3C2 which gives 2520.

1]. for selection of 7 batsman out of 10 no. of ways = 10C7

2]. for selection of 6 bowlers out of 7, no. of ways = 7C6

3]. for selection of 2 wicket keepers out of 3, no. of ways = 3C2

Total no. of ways = 10C7 X 7C6 X 3C2 = 2520

Very Simple 10C7 * 7C6 * 3C2 = 2520

The number of ways we can select 7 batsmen out of 10 is 10C7. similarly for selecting 6 out of 7 bowles is 7C6 and selecting 2 out of 3 wicket keepers is 3C2. Therefore the team can selected by total 2520 ways (10C7 * 7C6 * 3C2).

we can choose 7 out of 10 bats men in 10C7 ways and 6 out of 7 bowlers in 7C6 ways and then we can choose 2 out of 3 wicket keepers in 3C2 ways totally from fundemental principle of multiplication answer is 10C7 7C6 3C2=2520

Simple permutation and combination problem.(10C7)(7C6)(3C2)=2520

A combination of n objects taken r at a time is a selection which does not take into account the arrangement of the objects. That is, the order is not important.

formaula : NcR = n!/r!(n-r)!

10c7 * 7c6 * 3c2 = 2520

10C7 X 7C1 X 3C1 = 2520

use the formula n!/r!(n-r)! for batting,bowling and wiki(n is the total no and r is the no which we can choose)now multiply the results....120 7 33...if you are a beginner or searching for formulas and the concept on combinations and permutations visit the - http://www.mathsisfun.com/combinatorics/combinations-permutations.html

selecting 7 batsman = 10 C 7 selecting 6 bowlers = 7 C 6 selecting 2 wicket keepers = 3 C 2 so we get by multiplying all = 2520

nCr=nC(n-r). So 10C3 * 7C1 * 3c2 = 2520

(10c7)(7c6)(3c2)

10!/(7! * 3!) * 7!/6! * 3!/2! =2520......

C(10,7) x C(7,6) x C(3,2)