There are 6 cards with the numbers 1, 2, 3, 4, 5 and 6 written on them. The cards were turned over and shuffled.
You take 3 of the 6 cards.
Is it more likely that the sum of the numbers chosen are odd or even?
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You choose 3 out of 6 cards. The number of possible ways is 6x5x4/1x2x3= 20.
Now, assume the sum is odd. This can happen if all 3 cards are odd, or if 2 are even and 1 is odd.
There are only 3 odd cards in this deck of 6 cards, so the chances all 3 cards are odd is 1/20.
With the other case, the chances is (3x2/1x2 times 3)/20, which is 9/20.
The sum of the chances in both cases is 10/20, which is 1/2.
Hence, the chances of getting odd or even is the same.