Let and be concentric circles with radii and , respectively. A chord is drawn in with length . Extend to intersect in points and . If the length of can be expressed as , where and are positeve integers, find the value of .
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Let the midpoint of AB and CD be X, and O be the centre of the circles. Then O X ⊥ A B , C D , and A X = X B = 1 .
By Pythagoras', O X 2 = O A 2 − A X 2 C X 2 = O C 2 − O X 2 = 6 2 − ( 4 2 − 1 2 ) = 2 1 Thereofore C D = 2 C X = 2 2 1 , and so a + b = 2 + 2 1 = 2 3 .