Chord's length.

Geometry Level 4

Tangents are drawn to the parabola y 2 = 4 x y^{2} = 4x from ( 1 , 3 ) (1,3) . Find the length of chord of contact.

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The answer is 8.062.

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1 solution

Aniket Verma
Mar 4, 2015

Let a tangent y t = x + a t 2 yt = x + at^{2} on the given parabola where a = 1 a=1 .

Since it passes from ( 1 , 3 ) (1,3) therfore the above equation should pass through it and the equation becomes 3 t = 1 + t 2 3t = 1 + t^{2} .

solving this qudratic in t t we get t = 3 + 5 2 = t 1 t= \frac{3+\sqrt5}{2} = t_1 and t = 3 5 2 = t 2 t = \frac{3-\sqrt5}{2} = t_2

now we have two values of t t and the length of chord on a parabola from t 1 a n d t 2 t_1~ and ~t_2 is ( t 1 t 2 ) ( t 1 + t 2 ) 2 + 4 (t_1 - t_2)\sqrt{(t_1 + t_2)^{2} + 4} .

putting the value of t 1 a n d t 2 t_1 ~and~ t_2 we get length of chord = = 6 5 \sqrt65 = = 8.062 8.062

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