Christmas Problems: No.5

Calculus Level 3

Draw a white square and randomly choose a point in it.

  1. Split the square into 121 congruent squares and paint the central-most square black.
  2. For the remaining 120 squares, repeat Step 1.

If you repeat this indefinitely, what is the probability that the point you initially chose is on a white square?

Your square should look like a modified version of the diagram below. Instead of the square being drawn into 9 congruent squares, your square should be drawn into 121 congruent squares.

0 0 1 121 \frac { 1 }{ 121 } 241 14641 \frac { 241 }{ 14641 } 43561 1771561 \frac { 43561 }{ 1771561 } 1 2 \frac { 1 }{ 2 } 8 9 \frac { 8 }{ 9 } 120 121 \frac { 120 }{ 121 }

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1 solution

Kok Hao
Dec 29, 2017

After the first iteration, the area of the white squares will be 120 121 \frac { 120 }{ 121 } as 1 1 centre-most square will be painted black.

After the second iteration, the area of the white squares will be ( 120 121 ) 2 (\frac { 120 }{ 121 } )^{ 2 } as 1 121 \frac { 1 }{ 121 } of each of the 120 white squares will be painted black, leaving ( 120 121 ) ( 1 1 121 ) = ( 120 121 ) 2 (\frac { 120 }{ 121 } )(1-\frac { 1 }{ 121 } )=(\frac { 120 }{ 121 } )^{ 2 } as the total area of white squares after 2 iterations.

As you repeat this, you are taking out 120 121 \frac { 120 }{ 121 } of the previous iteration's area.

In general, the area of the remaining white squares after n n iterations is ( 120 121 ) n (\frac { 120 }{ 121 } )^{ n } .

Thus, when you repeat the process indefinitely, that means when n n approaches infinity, lim n ( 120 121 ) n = 0 \lim _{ n\rightarrow \infty }{ (\frac { 120 }{ 121 } } )^{ n }=\boxed{0}

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