How many ways are there of coloring the triangular prism's vertices using 4 distinct colors so that no two adjacent vertices share the same color ?
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Stand the figure as in the picture.
Use markers A to D before choosing colours. Use markers A, B and C for the top 3 vertices.
You then may use A, B and C for the bottom three vertices in 2 ways. Each of the combinations ABD, ACD, and BCD can be used for the bottom vertices in 3 ways. Making 11 ways total. Now A B and C can be replaced with a colour each in 4x3x2 = 24 ways. So, in total, there are 24 x 11 = 264 colour schemes.