Chuck Out Cubes
A set consists of positive integers (in increasing order) which are not the perfect cubes of any other positive integer. Find the remainder when the term of the set is divided by .
The answer is 12.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
12^3 < 2015 < 13^3 Hence, 2015 is the 2003rd term of K. (2003=2015-12) Therefore, the 2015th term of the sequence is 2027 .(make sure that 13^3 > 2027) 2027 leaves a remainder of 12 when divided by 2015 OR 2027 congruent to 12 modulo 2015. Hence the answer, 12.