1 4 2 8 5 7 × 2 = 2 8 5 7 1 4 1 4 2 8 5 7 × 3 = 4 2 8 5 7 1 1 4 2 8 5 7 × 4 = 5 7 1 4 2 8 1 4 2 8 5 7 × 5 = 7 1 4 2 8 5 1 4 2 8 5 7 × 6 = 8 5 7 1 4 2
You can see that the multiples of 142857 you would notice that they are just the permutation of digits 1,4,2,8,7,5.
Can you compute 1 4 2 8 5 7 × 7 ?
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The expression can be written as
142857*(2+5)=285714+714285=999999
Yes, a simple 7 = 1 + 6 or 7 = 2 + 5 or even 7 = 3 + 4 solves this problem.
Bonus question: What is so special about the number 142857 that every time you multiple it by an integer between 1 to 6, the resultant number is the rearrangement of digits of the original number? Can you find other numbers that share the same property?
Another Interesting thing to note— 1/7 = 0.142857142857142857... (repeating set of 142857)
@Chung Kevin did you see this?
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Yes I did! I'm wondering how many people got it wrong, and why.
Note that:
142+857=999
285+714=999
428+571=999 ...
and that:
14+28+57=99
42+85+71=2(99)
You can rearrange the numbers to get the others.
Also, (14)(28)(57)+(42)(85)(71)=275814, rearranged yet another way!
52631578947368421 works up to 19. If you're curious enough, you'll find that 52631578947368421 x 19 = 999999999999999999.
Since,
142857 x 7 = 142857 x 6 + 142857
Substituting the expression, we'll have,
142857 x 7 = 857142 +142857
142857 x 7 = 9 9 9 9 9 9
142857×7 = 142857× (10-3)= = (142857×10) - (142857×3)= = 1428570 - 428571= 999999! It was quite easy!
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Why use 2 + 5 when we can use 6 + 1 .
1 4 2 8 5 7 × 7 = 1 4 2 8 5 7 × ( 6 + 1 ) = 8 5 7 1 4 2 + 1 4 2 8 5 7 = 9 9 9 9 9 9 .