Chunk of Pi.

The area $A$ of a circle is given by $A = \pi r^2$ , where $r$ is the radius of the circle.

Since $A = r$ by hyphotesis, we have $r = \pi r^2$ , which means $1 = \pi r$ .

Since the circumference $L$ of a circle is given by $L = \pi (2 r)$ and $1 = \pi r$ , then $L = 2(1) = 1$ .

We are given $r=\pi r^{2}$ Dividing both sides by $r$ , we get $\pi r= 1$ then $r=\frac{1}{\pi}$ The formula for a circle's circumference is $2\pi r$ . Hence, the circumference is $2\times\pi\times\frac{1}{\pi}=2$

The radius of a circle is equal to its area.

• R = $\pi$ R ²
• 1 = $\pi$ R

The circumference of a circle is 2 $\pi$ R , then:

• 2 $\pi$ R = $2 \times 1$

Thus, the circle's circumference is 2 units.

pi x r x r = r, therefore. pi x r=1 therefore 2 x pi x r = 2

From the problem we know that $\pi r^2 = r$ , so $\pi r = 1$ , and $r = \frac{1}{\pi}$ . Plugging this in for circumference, we have $2\pi r= 2\pi\frac{1}{\pi} = 2$ .

Since area = radius

Therefore, $pi \times r * r$ = r

Hence, $pi \times r$ = 1

But, circumference of a circle is 2 * $pi \times r$ = $2 \times 1$ = 2

We Have πr²=r.....→ Dividing Throughout By ’r’ We Get πr=1.....eqn 1.....Now To Get Circumference i.e 2πr Simply multiply eqn 1 By 2 We Get 2πr=2.Thus Circumference =2

Let the radius be r. Let the area of circle = PI* r r. Now solving both we will get only PI r. -------------------------(1) Circumference of circle =2 PI r.-----------------------------------(2) Solving (1) &(2). We will only get 2.

area of circle = pi r^2. circumference of circle=2 pi r here r=pi r^2 r=1/pi circumference =2

The area of a circle is equal to $\pi r^2$ .

Since the area is numerically equal to the radius, we let $r$ be the area. Therefore,

$r = \pi r^2$

$\frac{r}{r^2} = \pi$

$\frac{1}{r} = \pi$

$r = \frac{1}{\pi}$

We now have the value for $r$ . Let's put it to the formula for the circumference of the circle, which is $C = 2 \pi r$ , since we are dealing with the radius.

$C = 2 \pi r$

$C = 2 \pi (\frac{1}{\pi})$

$C = \boxed{2}$

There. The circumference of the said circle is $2$ units.

since the area and the circumference are numerically equal πr^2=2πr then you solve the equation' then you get 2 as the answer.

In a sense you could also get -2 as the answer.

let the radius = r area=πr² area=r r=πr² divided by r 1=πr r=1/π circumference =2πr but r=1/π =2π/π=2

r=pi r^2

1/pi=r

C=1/pi x 2 x pi

C=2

Its very simple. Here $r=\pi r^2\Rightarrow\pi r=1$ . Hence $2\pi r=2$ which is the required circumference.

We know from that clue that r = phi x r^2 "areas" ---> So, 1 = phi x r ---> r = 1/ phi. Then, the solution is the circumference of circle is 2 x phi x r = 2 x phi x 1/phi = 2. Answer : 2

22/7 * x * x= x
x (radius)=7/22
Diameter=7/22 * 2= 7/11
Circumference=22/7 * 7/11=2