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I entered -6, needed that extra step to earn the credit for that exercise.
The solution is perfect. The way I understood is:
The big circle should have a r adius of CA + AD=
1
+
2
2
+
(
2
3
)
2
=
2
7
.
So the equation of the big circle is:-
(
x
+
2
)
2
+
(
y
+
2
3
)
2
=
(
2
7
)
2
.
⟹
x
2
+
4
x
+
4
+
y
2
+
3
y
+
4
9
=
4
4
9
.
∴
x
2
+
y
2
+
4
x
+
3
y
−
6
=
0
.
S
o
k
=
−
6
.
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As the value of k increases, the radius of the circle centered at ( − 2 , − 2 3 ) decreases. When this circle touches the given circle which is centered at origin, the value of k can be obtained as follows,
C D 2 2 + ( 2 3 ) 2 − k 4 2 5 − k k = A D + A C = 1 + 2 2 + ( 2 3 ) 2 = 2 7 = − 6
This is the case when the circles touch each other internally.
Hence, as per the condition required the maximum integer value of k is − 7 .