Circle Intersecting Circles

Geometry Level pending

Let ω 1 , ω 2 \omega_1, \omega_2 be distinct fixed circles on a flat plane. A third circle ω 3 \omega_3 in the same plane intersects ω 1 \omega_1 at exactly two distinct points A , B A, B and ω 2 \omega_2 at exactly two distinct points C , D . C, D. Lines A B AB and C D CD intersect at point P . P. Over all possible ω 3 , \omega_3, what is the locus of P ? P?

The situation described is impossible A pair of parallel lines A point A circle A line It depends on the placement of ω 1 \omega_1 and ω 2 \omega_2

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1 solution

Steven Yuan
Jul 11, 2017

Note that A B C D ABCD is cyclic, so ( P A ) ( P B ) = ( P C ) ( P D ) (PA)(PB) = (PC)(PD) by Power of a Point. However, ( P A ) ( P B ) (PA)(PB) is the power of point P P with respect to ω 1 , \omega_1, while ( P C ) ( P D ) (PC)(PD) is the power of P P with respect to ω 2 . \omega_2. This implies that the locus of P P is the set of all points X X such that the powers of X X with respect to ω 1 \omega_1 and to ω 2 \omega_2 are the same. This is just the radical axis of ω 1 \omega_1 and ω 2 , \omega_2, which we know to be a straight line. Thus, the locus of P P is a line .

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