A circle has a chord approximately 15.43 cm.. The smaller arc measures approximately 16.76 cm.. What is the radius of the circle?? Answer is understood already to be in cm..
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Let the angle that extend the chord be θ , then:
{ θ r = 1 6 . 7 6 2 r sin 2 θ = 1 5 . 4 3
Dividing the two equations, we have:
θ 2 sin 2 θ = 1 6 . 7 6 1 5 . 4 3 ⇒ sin 2 θ = 0 . 4 6 0 3 2 2 1 9 6 θ
We can use Newton's method to find θ . I implemented it with a spreadsheet (see below).
We find that θ = 1 . 3 9 6 9 9 4 7 3 3 rad ⇒ r = θ 1 6 . 7 6 = 1 . 3 9 6 9 9 4 7 3 3 1 6 . 7 6 = 1 1 . 9 9 7 1 8 1 9 5 ≈ 1 2