y = x 2 and the line y = − 2 1 x in Cartesian coordinates. A circle with center ( p , 0 ) , where p > 0 , is tangent to both the parabola and the line. What is the value of p rounded to three decimal places?
The above picture shows the graphs of the parabolaGraph generated in Desmos .
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Hello Ronak Agarwal, that's a very good solution. However, I also tried solving it using a different approach and I got the final answer as 6 4 8 3 0 + 1 3 0 6 5 which has the same value as your answer but in a different form. Can you please guide me on how to convert my answer into this form? f ( a + b ) ( − c + d e ) Thank you very much.
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actually the question has been wrongly asked i did get same and also converted it but the answer i received was different check this (8+sqrt(65))(sqrt(-28130+3490sqrt(65))/64
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We have the centre of the circle as A = ( x , 0 ) let the point of contact of circle and parabola be B = ( t , t 2 ) .
Ist equation we would be writing is that the tangent and AB is perpendicular to each other, hence we write :
( S l o p e o f t a n g e n t ) ( S l o p e A B ) = − 1
( 2 t ) ( t − x t 2 ) = − 1
rewriting it we have :
2 t 3 + t = x Equation 1
Second equation we would be writing is that :
length(AB)=Perpendicular distance from the line x + 2 y = 0
⇒ t 4 + ( t − x ) 2 = 5 x 2 Equation 2
Solving these two equations we get :
x = 1 2 8 ( 1 5 + 6 5 ) ( 2 6 5 − 2 )