Circle tells the area again

$A,B,C,D$ are 4 points on a 2-dimensional plane such that $\angle ACR=\angle ADS=\angle ABT$ . $CR,DS$ intersect at $G$ ; $DS,BT$ at $E$ and $CR,BT$ at $F$ . Points $A,E,F,G$ are concyclic. If $\frac{BD}{DC}=1.5$ ), where $BC>BD>CD$ and the area of the figure $ABCD$ equals 100; then what is the area of the triangle $ABD$ ?