Circles

Geometry Level 3

$A, B, C$ and $D$ are points on a circle.

$PA$ is a tangent to the circle.

$\angle PAD = 39 ^\circ$ and $\angle BCD = 103 ^\circ$ .

$BD$ is NOT a diameter

Find the measure of the angle $ADB$ .

Give your answer in degrees.

1 solution

Juvraj Singh
Mar 20, 2016

I posted this question. 64 degrees is the right answer, but I'm not sure how to get there. Any help would be greatly appreciated

$\angle PAD = \angle DBA = 39°$

$\angle BAD = 180° - \angle DCB$

$\angle BAD = 77°$

$180° - 77° - 39° = 64°$

國聰蕭 - 5 years, 2 months ago

Thank you so much, but one confusion: why is angle PAD=angle DBA?

Edit: don't worry, figured it out - alternate segment theorem. Thank you so much for the solution

Juvraj Singh - 5 years, 2 months ago