Circuit
Electricity and Magnetism
Level
2
a circuit consists of 3 resistors of resistance R each in parallel and a resistor 5 ohm in series are connected to a battery of p.d. 5 V. If the p.d. across the 5 ohm resistor is 2.5 V then find the value of 10 R.
The answer is 150.
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2 solutions
- Between A and B:
- V = 2.5 V
- R = 5 Ω
- I = V/R = 0.5 A
- Between B and C:
- Equivalent resistance = R 1 + R 1 + R 1 1 = 3 R
- Total current = 0.5 A (current is conserved)
- V = 2.5 V ( V A C = V A B + V B C )
- 2 . 5 = 0 . 5 3 R -> R = 1 5 .
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- find the current across 5 ohm resistor with voltage given as 2.5 V: I=V/R= 2.5/5= 0.5A
- The total value of resistors in parallel is= R/3
- the total resistance of ckt is (R/3 + 5)ohm, voltage across the total resistance is 5V and current is 0.5A therefore solving the eqn: V=IR gives R=15 and 10R=150
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