Circular Motion
A disc rotates at a constant angular velocity . A coin is placed at a distance 0.5 meter from the centre of the disc. Find the minimum value of the coefficient of the statis friction so that the coin doesn't slip over the disc.
Take .
The answer is 0.25.
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1 solution
Here we know that a mass when kept at an rotating object it experiences an external outward force namely centripetal force which will be equal to friction for staying at rest. Hence FC = mg @ and FC = mw^2r hence putting values @= w^2r /g or putting values @ =.25 where @ is coefficient of friction.